A dollar here, four bits there, but it added up.

这里一美元， 那里四位，但它加起来了。

In this case the opcode, which is the first four bits, is: 0010.

在这种情况下，操作码（前四位）是：0010。

The RAM address is the last four bits of our instruction which are 1110, or 14 in decimal.

RAM 地址是我们指令的最后四位，即 1110 或十进制的 14。

In our hypothetical example, we use the first four bits to store the “operation code”, or opcode for short.

在我们假设的例子中， 我们使用前四位来存储“操作码”，或简称操作码。

As we discussed, the first four bits of an instruction is the operation code, or OPCODE for short.

正如我们所讨论的，指令的前四位是操作码，或简称为 OPCODE。

The second set of four bits defines the memory location, in this case, 1110, which is 14 in decimal.

第二组四位定义内存位置，在本例中为 1110，十进制为 14。

There might actually be three or four bits, but by saying one or two, the man shows that there are a few things that we need to talk about

也许合同中还有三到四处，但是他说一到两处，实际上是指合同中的一些地方，我们还需要探讨。

The final four bits specify where the data for that operation should come from - this could be registers or an address in memory.

最后四位指定该操作的数据应来自何处 - 这可能是寄存器或内存中的地址。

So, our hypothetical CPU is very basic – all of its instructions are 8 bits long, with the opcode occupying only the first four bits.

所以，我们假设的 CPU 是非常基本的——它的所有指令都是 8 位长，操作码只占据前四位。

For our hypothetical CPU, the first four bits specified the operation code, or opcode, and the second set of four bits specified an address or registers.

对于我们假设的 CPU，前四位指定操作码或操作码，第二组四位指定地址或寄存器。

This instruction reads data from a location of memory specified in those last four bits of the instruction and saves it into Register A.

该指令从指令最后四位指定的内存位置读取数据，并将其保存到寄存器 A 中。

At a low level, this is done by writing the value specified in the last four bits into the instruction address register, overwriting the current value.

在低级别，这是通过将最后四位中指定的值写入指令地址寄存器，覆盖当前值来完成的。

We can assign an ID to each instruction supported by our CPU. In our hypothetical example, we use the first four bits to store the " operation code" , or opcode for short.

我们可以为我们的 CPU 支持的每条指令分配一个 ID。在我们假设的例子中，我们使用前四位来存储“操作码”，简称操作码。